Let's denote the number of board books Santiago bought as \( x \) and the number of soft cover books as \( y \). We are given two pieces of information:
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The total number of books Santiago bought is 34: \[ x + y = 34 \]
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The total cost of the books is $20, with board books costing $1.50 and soft cover books costing $0.50: \[ 1.5x + 0.5y = 20 \]
Now we have a system of two equations:
- \( x + y = 34 \)
- \( 1.5x + 0.5y = 20 \)
We can simplify the second equation by multiplying it by 2 to eliminate the decimal: \[ 3x + y = 40 \]
Now we have the new system of equations:
- \( x + y = 34 \) (1)
- \( 3x + y = 40 \) (2)
Next, we can solve this system. We can subtract equation (1) from equation (2): \[ (3x + y) - (x + y) = 40 - 34 \]
This simplifies to: \[ 2x = 6 \]
Dividing both sides by 2 gives: \[ x = 3 \]
Now we can substitute \( x = 3 \) back into equation (1): \[ 3 + y = 34 \] \[ y = 34 - 3 = 31 \]
So, Santiago bought:
- 3 board books and
- 31 soft cover books.
To verify, we can check both conditions:
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Total number of books: \[ 3 + 31 = 34 \quad \text{(Correct)} \]
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Total cost: \[ 1.5(3) + 0.5(31) = 4.5 + 15.5 = 20 \quad \text{(Correct)} \]
Thus, the solution is that Santiago bought 3 board books and 31 soft cover books.