A. To represent the situation with a two-variable equation, we define the variables as follows:
- Let \( h \) be the number of hard cover books.
- Let \( s \) be the number of soft cover books.
The cost of hard cover books is $2.00 each, and the cost of soft cover books is $1.00 each. Santiago spends a total of $30 on these books. Therefore, we can write the equation as:
\[ 2h + 1s = 30 \]
This equation models the total cost of the books Santiago purchased.
B. To check if it's possible that Santiago bought 10 hard cover books and 5 soft cover books, we will substitute \( h = 10 \) and \( s = 5 \) into the equation:
\[ 2(10) + 1(5) = 30 \]
Calculating the left side:
\[ 20 + 5 = 25 \]
Since \( 25 \) does not equal \( 30 \), this means that it is not possible for Santiago to have bought 10 hard cover books and 5 soft cover books. Therefore, the combination does not satisfy the equation.
In conclusion, the total amount spent by Santiago would need to match $30, and in this case, he only spent $25, which confirms that the combination of 10 hard cover books and 5 soft cover books is not valid based on the equation \( 2h + 1s = 30 \).