Samuel, Elis and David sell newspapers. One day David sold 20 newspapers more than Elis who sold 10 newspapers more than Samuel. The total number of newspapers they sold that day was 140. If Elis sold y newspapers, write the equations can be used to find the number of newspapers sold by Elis?

2 answers

Elis = y
Samuel = Elis - 10
David = Elis + 20
Total = 140
See if you can find y now.

Although looking at it it's not an whole number which is strange..
Elis --- y
Samuel --- y-10
David --- y+20

y+y-10+y+20 = 140
3y = 130
y = 130/3 = 43 1/3 newspapers ????

Something is rather bogus about your question.

Notice mathematically my answer is correct:
Elis sold 43 1/3
Samuel sold 33 1/3
David sold 63 1/3

43 1/3 + 33 1/3 + 63 1/3 = 140