Samples of NH3 and 02 are placed in a rigid container. When the equilibrium below is established, the partial pressure of H2O is 0.784 atm. What is the partial erasure of NO when the system is at equilibrium?

Question

Samples of NH3 and 02 are placed in a rigid container. When the equilibrium below is established, the partial pressure of H2O is 0.784 atm. What is the partial erasure of NO when the system is at equilibrium? 
4NH3 + 5O2 -----> 4NO + 6H2O

DrBob222 · Answer

......4NH3 + 5O2 -----> 4NO + 6H2O I......x......y..........0.....0 C....-4z.....-5z........+4z...+6z E.....x-4z..y-5z.........4z....6z pH2O = 6z = 0.784 from the problem z = ? Then NO is 4z = ?

123 · Answer

123