Let's assume the cost for each month is x and the cost of the fee is y.
According to plan 1, the total cost for 12 months plus the fee is $54.50, so we can write the equation:
12x + y = 54.50
According to plan 2, the total cost for 6 months plus the fee is $30.20, so we can write the equation:
6x + y = 30.20
We now have a system of equations:
12x + y = 54.50
6x + y = 30.20
To solve this system, we can either use substitution or elimination. Let's use elimination.
Subtracting the second equation from the first equation, we eliminate y:
12x + y - (6x + y) = 54.50 - 30.20
12x - 6x = 24.30
6x = 24.30
x = 24.30/6
x = 4.05
Now that we know x, we can substitute it into either equation to find y. Let's use the second equation:
6x + y = 30.20
6(4.05) + y = 30.20
24.30 + y = 30.20
y = 30.20 - 24.30
y = 5.90
Therefore, the cost for each month is $4.05, and the cost of the fee is $5.90.
Sam is shopping for a live streaming service so she can watch a new drama series during her free time. she sees that the live streaming service offers a couple of plans for new customers to choose from.
plan 1: 12 months plus the fee for a total of $54.50
plan 2: 6 months plus the fee for a total of $30.20
what is the cost for each month and what is the cost of the fee using algebraic methods?
1 answer