Sam is setting up the basic design for a product line for chocolate

Question

bars. The line needs to produce 200000 bars per eight hours shift and it run
continuously.The conveyor is 1m wide and each bar is 20mm wide and 60mm
long. if the length of line is 250m, at what average speed , khp , must it run

Answer 1

assuming the belt surface is covered with bars, then it makes sense to line them up 50 bars across (50*20=1000mm = 1m).
So, the 250m-log surface can hold 250/.06 = 4167 bars

Thus, the total surface of the belt can hold 4166*50 = 208,333 bars at once.

Thus only .96 belt-lengths per 8-hr shift is required.

.96*250m/8hr = 0.12 m/hr

I suspect that there are other considerations.