This is done the same way as the C2H5NH3Cl. I don't think I need to work this. Just follow my lead on the other problem. The equation you need is
...................NO2^- + HOH ==> HNO2 + OH^-
I.....................0.590.....................0...........0
C...................-x............................x............x
E..................0.590-x....................x...........x
I'll leave it with you.
Post your work if you get stuck.
Salt of a Strong Base and a Weak Acid. pH of Solution.
Calculate the pH of a 5.90×10-1 M aqueous solution of sodium nitrite (NaNO2).
(For nitrous acid, HNO2, Ka = 4.00×10-4).
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4 answers