Salmon often jump waterfalls to reach their breeding grounds. Starting 2.00 m from a waterfall 0.55 m in height, at what minimum speed must a salmon jumping at an angle of 32.0 degrees leave the water to continue up stream?

help plz...stuck....thx

11 answers

We have a parabola, with
y(0) = 0
y(2.0) = 0.55 is the vertex

That means its equation is y = 0.1375(4-(x-2)^2)

The slope at x=0 is 0.55
sin 32° = 0.53

So, the given data are not exact, but probably close enough. So, using 32° as our benchmark, with tan32° = 0.625, we need v such that

(v sin32°)^2/2g = 0.55
.281v^2/19.6 = 0.55
v = 6.19 m/s
Wth is a "help plz...stuck....thx"?
hey man, im stuck too bud, CRAP BRO, like wth
I'm literally crying rn :(
Salmon tend to swim in fresh water rivers, so I would advise googling the average speed of a river.
Steve you don’t show how you found v you just give us it with no context please explain
this question is epic :|
yall suck for not answering this and having a whole a*s convo <:/
s*ck^
so we all have physics this year huh
oh man physics does stuck but you can use honey :{/)