The easy way is mg = 50*9.8
Since they've given you all this info about the Earth I'm guessing they want
Fg = Gm1m2/r^2
= 6.67e-11*50*5.98e24/6.371e6^2
That force IS her weight
Sally has a mass of 50.0kg and earth has a mass of 5.98X10^24kg. The radius of earth is 6.371x10^6m.
A)What is the force of gravitational attraction between sally and earth?
B)What is Sally's weight?
2 answers
A) Use the formula Fg = (G)(m1)(m2)÷(r^2)
G = 6.67x10^-11 or 6.67e-11
m1 = mass of 1st object in kg
m2 = mass of second object in kg
r = distance between centers of the masses in meters
Can be rewritten as Fg = (6.67x10^-11)(50.0)(5.98x10^24)÷(6.371x10^6)^2
Fg = (1.99433x10^16)÷(6.371x10^6)^2
Answer = 491.34 newtons
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B) W = mg
m = mass in kg
g = gravity
W = (50.0)(9.8)
Answer = 490 newtons
G = 6.67x10^-11 or 6.67e-11
m1 = mass of 1st object in kg
m2 = mass of second object in kg
r = distance between centers of the masses in meters
Can be rewritten as Fg = (6.67x10^-11)(50.0)(5.98x10^24)÷(6.371x10^6)^2
Fg = (1.99433x10^16)÷(6.371x10^6)^2
Answer = 491.34 newtons
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B) W = mg
m = mass in kg
g = gravity
W = (50.0)(9.8)
Answer = 490 newtons
4 answers