Salim purchased a motorcycle and it depreciates each year. Its depreciation is represented by the function f(x) = 14000(1−0.09)x



When will the motorcycle be worth $7000?

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(1 point)
Responses

6.7 years
6.7 years

7 years
7 years

7.3 years
7.3 years

8 years

1 answer

To find out when the motorcycle will be worth $7000, we need to solve the equation given by the depreciation function for \( f(x) = 14000(1 - 0.09)^x \), where \( f(x) \) represents the value of the motorcycle after \( x \) years.

We can set this equal to $7000:

\[ 14000(1 - 0.09)^x = 7000 \]

First, divide both sides by 14000:

\[ (1 - 0.09)^x = \frac{7000}{14000} \]

This simplifies to:

\[ (1 - 0.09)^x = 0.5 \]

Next, calculate \( 1 - 0.09 \):

\[ 1 - 0.09 = 0.91 \]

So the equation becomes:

\[ 0.91^x = 0.5 \]

Now we can solve for \( x \) by taking the logarithm of both sides. Using the natural logarithm (you can also use any logarithm):

\[ \ln(0.91^x) = \ln(0.5) \]

Using the property of logarithms:

\[ x \ln(0.91) = \ln(0.5) \]

Now, we can solve for \( x \):

\[ x = \frac{\ln(0.5)}{\ln(0.91)} \]

Calculating the right side:

  1. \( \ln(0.5) \approx -0.6931 \)
  2. \( \ln(0.91) \approx -0.0943 \)

Now substitute these values:

\[ x \approx \frac{-0.6931}{-0.0943} \approx 7.35 \]

Thus, \( x \approx 7.3 \) years.

The motorcycle will be worth $7000 approximately after 7.3 years.