salary increases: A man gets a job with a salary of $30000 a year. He is promised a $2300 raise each subsequent year. Find the total earnings for a 10 year period.
Arithmetic Sequence,:
4 answers
30,000*10 + 2,300*45 = 403,500
arithmetic sequence
a = 30,000
d = 2,300
n = 10
sum n = 1 to n = 10
of a + d(n-1)
http://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html
= 10/2 (60,000 + 9 * 2,300)
a = 30,000
d = 2,300
n = 10
sum n = 1 to n = 10
of a + d(n-1)
http://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html
= 10/2 (60,000 + 9 * 2,300)
which by the way is what Olaf said :)
a sub 1 = $30,000
Use the arithmetic formula
a sub n = a sub 1 + d (n-1) to find how much the man makes in his 10th year, where d = the difference...in this case d = +2300
(When you plug this in it would look like a sub 10 = 30,000 + 2300(10-1) which equals $50700
Then, using this information, plug it into the equation S (sum) sub n equals
n [ (a sub 1 plus a sub n) / 2 ]
(When you plug this in it would look like
S sub 10 = [ (30k + 50700) / 2 ]
This gives you your answer, $403,500
Use the arithmetic formula
a sub n = a sub 1 + d (n-1) to find how much the man makes in his 10th year, where d = the difference...in this case d = +2300
(When you plug this in it would look like a sub 10 = 30,000 + 2300(10-1) which equals $50700
Then, using this information, plug it into the equation S (sum) sub n equals
n [ (a sub 1 plus a sub n) / 2 ]
(When you plug this in it would look like
S sub 10 = [ (30k + 50700) / 2 ]
This gives you your answer, $403,500
1 answer