SA=2πr2 + 2πrh

Answer 1

This equation represents the surface area of a cylinder.

The variables used in the equation are:
- SA: Surface area of the cylinder
- r: Radius of the base of the cylinder
- h: Height of the cylinder

Answer 2

solve it

Answer 3

To solve the equation, we can rewrite it in terms of either the radius (r) or the height (h). Let's solve it for the height (h) in terms of the surface area (SA) and the radius (r):

2πr^2 + 2πrh = SA

Subtract 2πr^2 from both sides:

2πrh = SA - 2πr^2

Divide both sides by 2πr:

h = (SA - 2πr^2) / (2πr)

Therefore, the equation solved for the height (h) is:

h = (SA - 2πr^2) / (2πr)

Answer 4

2*3.14*6^2 + 2*3.14*6*14

Answer 5

To evaluate the expression, substitute the given values into the equation:

SA = 2πr^2 + 2πrh

Where r = 6 and h = 14.

SA = 2 * 3.14 * 6^2 + 2 * 3.14 * 6 * 14

SA = 2 * 3.14 * 36 + 2 * 3.14 * 6 * 14

SA = 226.08 + 527.04

SA = 753.12

Therefore, the surface area of the cylinder is approximately 753.12.