S1

Question

Key = Space
LED1
R1
1500Ω
+
This is the circuit from Problem 2. You are given that the voltage between
R1 and LED1 is measured as 3.35V
How much current is flowing through all of the components of this circuit?

Answer 1

To find the current flowing through the circuit, we can use Ohm's Law, which states:

\[ I = \frac{V}{R} \]

where:

• \( I \) is the current (in Amperes),
• \( V \) is the voltage (in Volts),
• \( R \) is the resistance (in Ohms).

In your circuit, we know:

• The voltage across the resistor \( R1 \) and the LED \( LED1 \) is provided as 3.35V.
• The resistance \( R1 \) is given as 1500Ω (or 1.5kΩ).

Now we can substitute the values into Ohm’s Law to find the current:

\[ I = \frac{V}{R} = \frac{3.35V}{1500Ω} \]

Calculating this gives:

\[ I = \frac{3.35}{1500} \approx 0.002233 A \]

To convert this to milliamperes (mA):

\[ I \approx 2.233 mA \]

Therefore, the current flowing through all of the components of the circuit is approximately 2.23 mA.

Answer 2

V: 3.35 V
V(p-p): 3.54 pV
V(rms): 3.35 V
V(dc): 3.35 V
V(freq): 24.1 kHz

Answer 3

It looks like you've provided additional voltage measurements and frequency information, but it's not entirely clear how this data relates to your previous question regarding current in the circuit. Here's a breakdown of the values you've provided:

1. V (Voltage): 3.35 V - This is likely the DC voltage across the components (R1 and LED1).
2. V(p-p) (Peak-to-Peak Voltage): 3.54 pV - This value is quite small and suggests it might not be relevant to your current calculation (at least it doesn't seem consistent with the other voltage values, possibly indicating a measurement error or confusion).
3. V(rms) (Root Mean Square Voltage): 3.35 V - RMS voltage is typically utilized for AC measurements, but since your previous context suggests a DC scenario, this value may also just represent a steady DC.
4. V(dc) (DC Voltage): 3.35 V - This aligns with the initial measure across R1 and LED1.
5. V(freq) (Frequency): 24.1 kHz - This seems to indicate that there may be an AC component or modulation present in your circuit.

Given that the DC voltage is consistently mentioned as 3.35 V, you can refer back to the previous Ohm's law calculation. The current flowing through the circuit as calculated earlier, without additional context indicating an AC analysis, is:

\[ I \approx 2.233 \text{ mA} \]

If your circuit is indeed alternating (affected by the frequency of 24.1 kHz), more information would be needed about the nature of the components (especially if they're reactive, like capacitors or inductors), and their impedances would need to be considered instead of simple resistances.

If you have any specific questions or need clarification based on these new parameters, please let me know!