S is the set of real numbers that are less than 15
10 answers
S = {x ∈ ℝ | x < 15}
5r+8<63
To solve the inequality 5r + 8 < 63, we can start by isolating the variable r on one side of the inequality.
5r + 8 < 63
Subtracting 8 from both sides:
5r < 55
Next, we can divide both sides of the inequality by 5 to solve for r:
r < 11
Therefore, the solution to the inequality 5r + 8 < 63 is r < 11.
5r + 8 < 63
Subtracting 8 from both sides:
5r < 55
Next, we can divide both sides of the inequality by 5 to solve for r:
r < 11
Therefore, the solution to the inequality 5r + 8 < 63 is r < 11.
7-3d⪰28
To solve the inequality 7 - 3d ≥ 28, we can start by isolating the variable d on one side of the inequality.
7 - 3d ≥ 28
Subtracting 7 from both sides:
-3d ≥ 21
Next, we can divide both sides of the inequality by -3. When multiplying or dividing both sides of an inequality by a negative number, it is important to remember to reverse the inequality symbol.
d ≤ -7
Therefore, the solution to the inequality 7 - 3d ≥ 28 is d ≤ -7.
7 - 3d ≥ 28
Subtracting 7 from both sides:
-3d ≥ 21
Next, we can divide both sides of the inequality by -3. When multiplying or dividing both sides of an inequality by a negative number, it is important to remember to reverse the inequality symbol.
d ≤ -7
Therefore, the solution to the inequality 7 - 3d ≥ 28 is d ≤ -7.
2(3p-11)⪰-16
To solve the inequality 2(3p-11) ≥ -16, we can start by distributing the 2 to the terms inside the parentheses.
6p - 22 ≥ -16
Next, we can add 22 to both sides of the inequality:
6p ≥ 6
Finally, we divide both sides of the inequality by 6 to solve for p:
p ≥ 1
Therefore, the solution to the inequality 2(3p-11) ≥ -16 is p ≥ 1.
6p - 22 ≥ -16
Next, we can add 22 to both sides of the inequality:
6p ≥ 6
Finally, we divide both sides of the inequality by 6 to solve for p:
p ≥ 1
Therefore, the solution to the inequality 2(3p-11) ≥ -16 is p ≥ 1.
{1}
"{1}" represents a set that contains only the element 1.
{-2,2}