S is surrounded by electrons, so the Lewis structure for SF6 does not follow the octet rule

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Yes, that is correct. In the Lewis structure of SF6, sulfur (S) is surrounded by six fluorine (F) atoms. Sulfur in its ground state has six valence electrons, and each fluorine atom contributes one valence electron, resulting in a total of 12 valence electrons. To satisfy the octet rule (except for hydrogen and helium), each atom needs eight valence electrons in its outer shell. However, in SF6, sulfur has 12 valence electrons around it, exceeding the octet rule. This is because sulfur can expand its octet and accommodate more than eight electrons, as it has empty d orbitals available for bonding.
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