(12x+6)(3x^2+3x+5)^7 dx
= 2(3x^2+3x+5)^7 (6x+3) dx
Let
u = 3x^2+3x+5
du = 6x+3 dx
so, now your integrand is just
2u^7 du
not so hard now, eh?
S(12x+6)(3x^2+3x+5)^7
S=integral sign
please help I am stuck :(
1 answer