the "rule" here is that
e^ln(k) = k
so e^(2lnx)
= e^ln(x^2)
= x^2
and
2) e^(-lnx)
= e^ln(x^-1)
= x^-1
or 1/x
Rules of Logarithms: Can someone explain how to do:
1) e^(2(ln)(x))
2) e^(-lnx)
I know the rules I just don't understand how they apply..
thanks!
2 answers
This is not the trigonometry I studied in high school