To determine the total energy Ronald put into the inclined plane, we can use the efficiency formula:
\[ \text{Efficiency} = \frac{\text{Useful output energy}}{\text{Input energy}} \times 100% \]
Given that the efficiency is 35% (or 0.35 as a decimal) and the useful output energy is 224 joules, we can rearrange the formula to find the input energy (the energy Ronald put into the inclined plane):
\[ \text{Input energy} = \frac{\text{Useful output energy}}{\text{Efficiency}} \]
Plugging in the values:
\[ \text{Input energy} = \frac{224 \text{ joules}}{0.35} \]
Calculating that:
\[ \text{Input energy} = 640 \text{ joules} \]
So, Ronald put 640 joules of energy into the inclined plane.
The correct response is 640 joules.
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