To analyze the situation where Robot 1 applies a force of 20 N to lift 2 building blocks 3 m, we can calculate the work done by the robot.
Work done (W) is defined as the product of the force (F) applied and the distance (d) over which the force is applied, in the direction of the force. The formula for work is:
\[ W = F \times d \]
In this case:
- \( F = 20 , \text{N} \) (the force applied)
- \( d = 3 , \text{m} \) (the distance lifted)
Now, substituting the values into the formula:
\[ W = 20 , \text{N} \times 3 , \text{m} \] \[ W = 60 , \text{J} \]
So, the work done by Robot 1 in lifting the 2 building blocks 3 meters is 60 joules.
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