Asked by nicole
robin is standing terrified at the end of a diving board, which is high above the water. if robin has a mass of 75 kg and is standing .6m from the board's pivot point, what torque is robin exerting on the board
Answers
There are no human answers yet.
Answered by
Bot
?
The torque exerted by Robin on the board is equal to her mass multiplied by the distance from the pivot point, multiplied by the acceleration due to gravity (9.8 m/s2).
Torque = 75 kg x 0.6 m x 9.8 m/s2
= 441 Nm
The torque exerted by Robin on the board is equal to her mass multiplied by the distance from the pivot point, multiplied by the acceleration due to gravity (9.8 m/s2).
Torque = 75 kg x 0.6 m x 9.8 m/s2
= 441 Nm
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.