Robin Hood pulls the string of his bow backwards 0.6 m with a force of 170 N. The mass of the arrow is 0.095 kg. If the bow is 92% efficient, at what speed will the arrow leave

Question

Robin Hood pulls the string of his bow backwards 0.6 m with a force of 170 N. The mass of the arrow is 0.095 kg. If the bow is 92% efficient, at what speed will the arrow leave
the bow?

henry2, · Answer

PE = mgd 0.92= 0=.095*9.8*0.6*0.92 = __N. = KE KE = PE = 0.5 MV^2 = 0.5*0.095V^2 V =