since distance = speed * time
4(s-20) = 3(s+20)
and we know what airspeed: it's its speed in the air. (note apostrophe)
Robin flies to San Francisco from LA in 4 hours. she flies back in 3 hours. if the wind is blowing from the north at velocity of 20mph during both flights, what was the airspeed of the plane (it's speed in the air)?
2 answers
I think we are to assume that San Francisco is just about north of LA
airspeed of plane ---- x mph
speed from SF to LA --- x + 20
speed from LA to SF ---- x - 20
distance one way = 4(x-20)
distance the other way = 3(x+20)
same distance, so
4x - 80 = 3x + 60
x = 140
speed of plane was only 140 mph ???
check:
4(120) =480
3(160) = 480
airspeed of plane ---- x mph
speed from SF to LA --- x + 20
speed from LA to SF ---- x - 20
distance one way = 4(x-20)
distance the other way = 3(x+20)
same distance, so
4x - 80 = 3x + 60
x = 140
speed of plane was only 140 mph ???
check:
4(120) =480
3(160) = 480