P = Po(1+r)^n.
r = 0.04/12 = 0.0033 = monthly % rate.
n = 40 compounding periods.
P = X(1+0.00333)^40 = 4200+4212.39
1.1422x = 8412.39
X = 7364.91
RM X was deposited in a savings account at 4.0% interest compounded monthly. Forty later, RM 4,200 was withdrawn from the account and the balance was RM 4,212.39. Find the value of X.
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