To find the length of side AB using the tangent ratio in triangle ABC, we can set up the following relationship:
\[ \tan(C) = \frac{\text{opposite side}}{\text{adjacent side}} \]
In triangle ABC:
- The angle C is 26 degrees.
- The opposite side to angle C is side AB.
- The adjacent side to angle C is the base AC, which is given as 15.
Thus, we can set up the equation:
\[ \tan(26^\circ) = \frac{AB}{15} \]
To solve for side AB, we rearrange the equation:
\[ AB = 15 \cdot \tan(26^\circ) \]
Now, we need to calculate \( \tan(26^\circ) \):
- Using a calculator, we find:
\[ \tan(26^\circ) \approx 0.4877 \]
Substituting this value back into the equation for side AB:
\[ AB \approx 15 \cdot 0.4877 \approx 7.315 \]
Rounding this value gives us:
\[ AB \approx 7.32 \]
Thus, the correct answer is:
side AB = 7.32