To find the angle formed between the top of the volleyball-net pole and the rope, we can use some basic trigonometry.
First, let's visualize the situation. We have a right triangle where:
- The height of the pole (the opposite side) is \(8\) feet.
- The distance from the base of the pole to the point where the rope is tied (the adjacent side) is \(5\) feet.
We can use the tangent function, which relates the angle \( \theta \) formed between the top of the pole and the rope:
\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{8}{5} \]
Now, we can find \( \theta \) by taking the arctangent:
\[ \theta = \tan^{-1}\left(\frac{8}{5}\right) \]
Now, let's calculate \( \theta \):
\[ \theta \approx \tan^{-1}(1.6) \]
Using a calculator:
\[ \theta \approx 58.0^\circ \]
Thus, the angle formed between the top of the pole and the rope, rounded to the nearest whole degree, is:
\[ \boxed{58} \]