since it hit head-on, the balls travel in exactly opposite directions, or in the same direction.
Aside from that, since the balls are of almost identical mass, do you really expect one of them to take off at 3 times the original speed?
to conserve momentum,
.17(2.4) = .17v + .16(2.13)
v = .395
That is, the cue ball almost came to a stop, and virtually all of its momentum was transferred to the 8-ball. The cue ball is still traveling slowly in its original direction.
Rick is playing billiards and hits the cue ball. It makes contact with the 8 ball head on. If before the collision the cue ball was travelling at 2.4 m/s and after the collision the 8 ball was traveling at 2.13 m/s. How fast and in what direction is the cue ball traveling? (Mass of cue ball=.17kg and mass of 8 ball=.16kg)
---I found the velocity of the cue ball to be 7.04 m/s but I don't know how to find the direction.. Help and thx!!!
3 answers
Head on means the ball stays on the same path, or reverse. Which? use algebra, and the law of conservation of moentum
momentum before=momentum after
M*2.4=MV1+MV2
= MV1+2.13M
V1= 2.4-2.13 which is positve, in the same direction it started in.
momentum before=momentum after
M*2.4=MV1+MV2
= MV1+2.13M
V1= 2.4-2.13 which is positve, in the same direction it started in.
Okay, so i did my math wrong sorry and thx Steve!! and bobpursley, does that mean the cue ball is traveling .27 m/s straight?? because usually they want angle but since it's head on it's just straight rite?