Richard has $652 in his account and is planning a road trip. He looks at how expensive hotels and sightseeing costs are in certain cities, planning accordingly:

City
Cost ($)
Detroit
196.87
Pittsburgh
180.32
St. Paul
102.87
Cincinnati
155.81
Richmond
211.86

When Richard makes the calculations, he finds he does not have enough money to visit each city. What is the cheapest city that Richard can drop to avoid overdrawing his account?
a.
Richmond
b.
Detroit
c.
Pittsburgh
d.
Cincinnati

1 answer

To determine which city Richard can drop to avoid overdrawing his account, we first need to calculate the total cost of visiting all cities, and then see how much he would need to drop from that total to stay within his budget of $652.

We can sum the costs of visiting each city:

  • Detroit: $196.87
  • Pittsburgh: $180.32
  • St. Paul: $102.87
  • Cincinnati: $155.81
  • Richmond: $211.86

Total Cost = $196.87 + $180.32 + $102.87 + $155.81 + $211.86

Now let's do the calculation:

\[ 196.87 + 180.32 + 102.87 + 155.81 + 211.86 = 847.73 \]

The total cost of visiting all five cities is $847.73.

Next, we find out how much overbudget Richard is:

\[ 847.73 - 652 = 195.73 \]

Richard is $195.73 over budget, so he needs to drop one of the cities to save at least that much.

Now we'll check the costs of each city:

  1. Richmond: $211.86
  2. Detroit: $196.87
  3. Pittsburgh: $180.32
  4. Cincinnati: $155.81

If he drops each city's cost:

  • Dropping Richmond saves $211.86 (so he's under budget)
  • Dropping Detroit saves $196.87 (so he's under budget)
  • Dropping Pittsburgh saves $180.32 (still over budget)
  • Dropping Cincinnati saves $155.81 (still over budget)

The cheapest city he can drop that will bring him under budget is Cincinnati with a cost of $155.81.

Therefore, the answer is: C. Pittsburgh, as dropping this city saves sufficient funds to bring Richard under budget, making it the optimal choice.