To solve for \( m\angle MNO \) in rhombus \( LMNO \):
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Properties of Rhombus: In a rhombus, the diagonals bisect each other at right angles and the opposite angles are equal.
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Given Information: You are given that \( m\angle MNL = 55^\circ \).
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Using the Angles: In rhombus \( LMNO \):
- Since the diagonals bisect the angles, we know that: \[ m\angle MNL = m\angle NLM \] Hence: \[ m\angle NLM = 55^\circ \]
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Finding Angles in a Rhombus: The measure of opposite angles in a rhombus are equal, and adjacent angles are supplementary (they add up to \( 180^\circ \)): \[ m\angle MNO + m\angle NLM = 180^\circ \] Substituting known values: \[ m\angle MNO + 55^\circ = 180^\circ \]
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Solving for \( m\angle MNO \): \[ m\angle MNO = 180^\circ - 55^\circ = 125^\circ \]
Thus, the measure of angle \( m\angle MNO \) is \( 125^\circ \).
Final Answer: \[ m\angle MNO = 125^\circ \]