Rewrite the irrational square root 48−−√

Question

as the product of an integer and another irrational square root.(1 point)
Responses

224−−√
2 start root 24 end root

43–√
4 start root 3 end root

212−−√
2 start root 12 end root

412−−√

Answer 1

To rewrite $\sqrt{48}$ as the product of an integer and another irrational square root, we can factor 48.

First, notice that:

$$48=16\times 3$$

Now we can rewrite the square root:

$$\sqrt{48}=\sqrt{16\times 3}=\sqrt{16}\times \sqrt{3}=4\sqrt{3}$$

So, $\sqrt{48}$ can be expressed as $4\sqrt{3}$.

Therefore, the correct response is:

4√3