Rewrite the irrational square root 48−−√ as the product of an integer and another irrational square root.(1 point)

Question

Responses

43–√
4 start root 3 end root

412−−√
4 start root 12 end root

212−−√
2 start root 12 end root

224−−√

Answer 1

To simplify \( \sqrt{48} \) as the product of an integer and another irrational square root, we can start by factoring 48 as follows:

\[ 48 = 16 \cdot 3 \]

Since \( \sqrt{16} = 4 \), we can rewrite \( \sqrt{48} \):

\[ \sqrt{48} = \sqrt{16 \cdot 3} = \sqrt{16} \cdot \sqrt{3} = 4\sqrt{3} \]

So, the correct response is:

4√3