The correct answer is O 2 * root(6, 3).
To rewrite the irrational cube root root(48, 3) as a product of an integer and another irrational cube root, we need to find a perfect cube that divides 48.
48 can be divided by 8, which is a perfect cube. So, we can rewrite root(48, 3) as root(8 * 6, 3).
Taking the cube root of 8, we get 2. Therefore, root(8, 3) is equal to 2.
Hence, root(48, 3) can be written as 2 * root(6, 3).
Rewrite the irrational cube root root(48, 3) as a product of an integer and another irrational cube root.
O 2 * root(6, 3)
O 4 * root(3, 3)
O - 2 * root(6, 3)
(1 point)
O 4 * root(12, 3)
1 answer
1 answer