Rewrite the irrational cube root 48−−√3 as a product of an integer and another irrational cube root.(1 point)

Answer 1

The irrational cube root of 48 can be written as a product of an integer and another irrational cube root as 2∛2.

Answer 2

wrong

Answer 3

Apologies for the incorrect answer. Let's find the correct answer.

To express the irrational cube root of 48 as a product of an integer and another irrational cube root, we need to find a cube root that can be simplified from 48.

Since 48 is divisible by 8, we can simplify the cube root of 48 as follows:

√3∛48 = √3∛8 * ∛6 = 2∛2 * ∛6

So, the irrational cube root of 48 can be written as a product of an integer (2) and another irrational cube root (∛2 * ∛6).