Rewrite the irrational cube root 189−−−√3

as the product of an integer and another irrational cube root. Show your work.

1 answer

To rewrite the irrational cube root \( \sqrt[3]{189} \) as the product of an integer and another cube root, we can start by factoring the number under the cube root.

  1. Factor 189: \[ 189 = 3^3 \times 7 \]

  2. Now, we can express \( \sqrt[3]{189} \) using this factorization: \[ \sqrt[3]{189} = \sqrt[3]{3^3 \times 7} \]

  3. Using the property of cube roots \( \sqrt[3]{a \times b} = \sqrt[3]{a} \times \sqrt[3]{b} \), we can separate the terms: \[ \sqrt[3]{189} = \sqrt[3]{3^3} \times \sqrt[3]{7} \]

  4. \( \sqrt[3]{3^3} \) simplifies to 3: \[ \sqrt[3]{3^3} = 3 \]

  5. Therefore, we can express \( \sqrt[3]{189} \) as: \[ \sqrt[3]{189} = 3 \times \sqrt[3]{7} \]

In conclusion, \( \sqrt[3]{189} \) can be rewritten as the product of an integer and another cube root: \[ \sqrt[3]{189} = 3\sqrt[3]{7} \]