Rewrite the following expressions: 2712⋅2714.(1 point)

Responses

27−−√4
root index 4 Start Root 27 End Root

2734
27 superscript Start Fraction 3 over 4 End Fraction baseline

2718
27 superscript Start Fraction 1 over 8 End Fraction baseline

27−−√3

1 answer

To rewrite the expression \(2712 \cdot 2714\), we can apply the properties of exponents.

First, we can rewrite \(2712\) and \(2714\) in terms of exponent base \(27\):

\[ 2712 = 27^{12} \quad \text{and} \quad 2714 = 27^{14} \]

Now we can combine these two using the property of exponents:

\[ 2712 \cdot 2714 = 27^{12} \cdot 27^{14} = 27^{12 + 14} = 27^{26} \]

Thus, \(2712 \cdot 2714\) can be rewritten as:

\[ 27^{26} \]

Now, let's evaluate the given options based on this:

  1. \(27^{\sqrt{4}} = 27^2\)
  2. \(27^{\frac{3}{4}}\)
  3. \(27^{\frac{1}{8}}\)
  4. \(27^{\sqrt{3}}\)

None of these options matches \(27^{26}\).

Combining in a different way, we can note that:

\[ 2712 \cdot 2714 = (27^{13})^2 - 1^2 \quad \text{(using difference of squares)} \]

Thus, another expression could be given as:

\[ (27^{13})^2 - 1^2 = 27^{26} - 1 \]

In conclusion, the most direct rewriting for the expression is \(27^{26}\). If we need to find a form from the options, none is equivalent to \(27^{26}\).

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