Rewrite the following equation into a quadratic equation and solve by factoring: x2+3x=6x+10

. Which of the following contains the correct values for x?(1 point)
Responses

−2
, 5
negative 2 , 5

2, −5
2, negative 5

2, 5
2, 5

−2
, −5
negative 2 , negative 5
Skip to navigation
page 18 of 18

1 answer

To rewrite the given equation \( x^2 + 3x = 6x + 10 \), we first bring all terms to one side of the equation:

\[ x^2 + 3x - 6x - 10 = 0 \]

Now, we combine like terms:

\[ x^2 - 3x - 10 = 0 \]

Next, we factor the quadratic equation \( x^2 - 3x - 10 \). We look for two numbers that multiply to \(-10\) and add up to \(-3\). The numbers that work are \(-5\) and \(2\). So, we can factor the equation as follows:

\[ (x - 5)(x + 2) = 0 \]

We set each factor equal to zero:

  1. \( x - 5 = 0 \) → \( x = 5 \)
  2. \( x + 2 = 0 \) → \( x = -2 \)

Thus, the solutions to the equation are \( x = 5 \) and \( x = -2 \).

The correct response from the options provided is:

−2, 5 (negative 2 , 5).