To rewrite the given equation \( x^2 + 3x = 6x + 10 \), we first bring all terms to one side of the equation:
\[ x^2 + 3x - 6x - 10 = 0 \]
Now, we combine like terms:
\[ x^2 - 3x - 10 = 0 \]
Next, we factor the quadratic equation \( x^2 - 3x - 10 \). We look for two numbers that multiply to \(-10\) and add up to \(-3\). The numbers that work are \(-5\) and \(2\). So, we can factor the equation as follows:
\[ (x - 5)(x + 2) = 0 \]
We set each factor equal to zero:
- \( x - 5 = 0 \) → \( x = 5 \)
- \( x + 2 = 0 \) → \( x = -2 \)
Thus, the solutions to the equation are \( x = 5 \) and \( x = -2 \).
The correct response from the options provided is:
−2, 5 (negative 2 , 5).