Rewrite the equation by completing the square.

\[x^{2}-2x+1 = 0\]
\[(x + {}\]

\[)^2 = {}\]

1 answer

To complete the square for the equation \(x^{2} - 2x + 1 = 0\), we can follow these steps:

  1. Start with the expression \(x^2 - 2x + 1\).
  2. Notice that the expression can be rewritten as a perfect square. Specifically, we can see that: \[ x^2 - 2x + 1 = (x - 1)^2 \]
  3. Therefore, the equation \(x^{2} - 2x + 1 = 0\) can be written as: \[ (x - 1)^2 = 0 \]

Putting this into the format you requested:

\[ (x + \text{ })^2 = \text{ } \]

This gives:

\[ (x - 1)^2 = 0 \]

So, we have completed the square as follows:

\[ (x - 1)^2 = 0 \]

Thus, the final rewritten form is:

\[ (x + (-1))^2 = 0 \]

So, to explicitly answer your format:

\[ (x + (-1))^2 = 0 \]

Here, the blank for \(x + \text{ }\) is \(-1\) and the blank for the other side is \(0\).

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