Rewrite the equation 4x/3x−12+3=10 in two equations joined by “and.

6 answers

To rewrite the equation \( \frac{4x}{3x-12} + 3 = 10 \) in two equations joined by "and," we can first isolate the fraction on one side of the equation.

  1. Start with the original equation: \[ \frac{4x}{3x - 12} + 3 = 10 \]

  2. Subtract 3 from both sides: \[ \frac{4x}{3x - 12} = 10 - 3 \] This simplifies to: \[ \frac{4x}{3x - 12} = 7 \]

Now, we can write the equation as two separate equations:

  1. The first equation is the isolated fraction: \[ \frac{4x}{3x - 12} = 7 \]

  2. The second equation is the derived part: \[ 3x - 12 \neq 0 \]

So, we can combine these into the final form:

\[ \frac{4x}{3x - 12} = 7 \quad \text{and} \quad 3x - 12 \neq 0 \]

whats the answer

The equation \( \frac{4x}{3x - 12} + 3 = 10 \) can be rewritten as two separate equations joined by "and" as follows:

\[ \frac{4x}{3x - 12} = 7 \quad \text{and} \quad 3x - 12 \neq 0 \]

This means the first equation is the altered form of the original equation, and the second equation indicates that the denominator cannot be zero.

So your final answer is:

\[ \frac{4x}{3x - 12} = 7 \quad \text{and} \quad 3x - 12 \neq 0 \]

i dont understand can u write it simpler

Sure! Here's a simpler breakdown:

  1. Start with the original equation: \[ \frac{4x}{3x - 12} + 3 = 10 \]

  2. First, we isolate the fraction:

    • Subtract 3 from both sides: \[ \frac{4x}{3x - 12} = 7 \]
  3. The second part ensures that the denominator is not zero:

    • The denominator \(3x - 12\) cannot be zero. So we write: \[ 3x - 12 \neq 0 \]

Putting it all together, we have:

\[ \frac{4x}{3x - 12} = 7 \quad \text{and} \quad 3x - 12 \neq 0 \]

This means:

  1. \( \frac{4x}{3x - 12} = 7 \) is the main equation.
  2. \( 3x - 12 \neq 0 \) makes sure the denominator isn't zero.

That’s the answer in a simplified form!

Lmao
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