rewrite f(x)=x^(2)-6x+2 in vertex form

Answer 1

To rewrite the function f(x) = x^2 - 6x + 2 in vertex form, follow these steps:

1. Complete the square for the quadratic term.
f(x) = (x^2 - 6x) + 2
f(x) = (x^2 - 6x + 9) - 9 + 2
f(x) = (x - 3)^2 - 7

2. Rewrite the constant term.
f(x) = (x - 3)^2 - 7

Therefore, the function f(x) = x^2 - 6x + 2 can be written in vertex form as f(x) = (x - 3)^2 - 7.