To review the graphs of the system of equations, let's first solve the equations for the solution.
Given the system of equations:
1) x - 5y = 7
2) 3x - 2y = -4
To solve this system, there are several methods you can use, such as substitution, elimination, or graphing. Here, I will use the method of substitution.
From equation 1) we get:
x = 7 + 5y
Substituting this value of x into equation 2), we have:
3(7 + 5y) - 2y = -4
21 + 15y - 2y = -4
13y = -25
y = -25/13
Substituting the value of y into equation 1), we find:
x - 5(-25/13) = 7
Multiply both sides by 13 to clear the fraction:
13x + 125 = 91
13x = -34
x = -34/13
So, the solution to both equations is x = -34/13 and y = -25/13.
Now, let's plot the graphs of these equations to find the intersection point.
To graph equation 1), we rearrange it as:
y = (x - 7)/5
To graph equation 2), we rearrange it as:
y = (3x + 4)/2
Using these equations, we can plot the graphs:
Equation 1):
Let x = 0, then y = (0 - 7)/5 = -1.4
Let x = 5, then y = (5 - 7)/5 = -0.4
Equation 2):
Let x = 0, then y = (3(0) + 4)/2 = 2
Let x = -4/3, then y = (3(-4/3) + 4)/2 = 0
Plotting these points and drawing the lines, we get the intersection point at (-34/13, -25/13):
Graph of the system of equations:

Therefore, the intersection point is (-34/13, -25/13).
Review the graphs of the system of two linear equations in two variables: x- 5y = 7 and 3x- 2y = -4. Find the solution to both equations. The intersection point is ?
3 answers
That's not correct
I apologize for the error in my previous response. Let's solve the system of equations correctly.
Given the system of equations:
1) x - 5y = 7
2) 3x - 2y = -4
We will solve this system using the method of elimination.
Multiply equation 1) by 3 and equation 2) by 1:
3(x - 5y) = 3(7) --> 3x - 15y = 21
1(3x - 2y) = 1(-4) --> 3x - 2y = -4
Now, subtract equation 2) from equation 1) to eliminate x:
(3x - 15y) - (3x - 2y) = 21 - (-4)
-15y + 2y = 21 + 4
-13y = 25
y = -25/13
Substitute the value of y into equation 1) to solve for x:
x - 5(-25/13) = 7
x + 125/13 = 7
x = 7 - 125/13
x = 91/13 - 125/13
x = -34/13
Therefore, the solution to both equations is x = -34/13 and y = -25/13.
Now, let's plot the graphs of these equations to verify the intersection point.
Graph of the system of equations:

As shown in the graph, the intersection point is indeed (-34/13, -25/13).
Given the system of equations:
1) x - 5y = 7
2) 3x - 2y = -4
We will solve this system using the method of elimination.
Multiply equation 1) by 3 and equation 2) by 1:
3(x - 5y) = 3(7) --> 3x - 15y = 21
1(3x - 2y) = 1(-4) --> 3x - 2y = -4
Now, subtract equation 2) from equation 1) to eliminate x:
(3x - 15y) - (3x - 2y) = 21 - (-4)
-15y + 2y = 21 + 4
-13y = 25
y = -25/13
Substitute the value of y into equation 1) to solve for x:
x - 5(-25/13) = 7
x + 125/13 = 7
x = 7 - 125/13
x = 91/13 - 125/13
x = -34/13
Therefore, the solution to both equations is x = -34/13 and y = -25/13.
Now, let's plot the graphs of these equations to verify the intersection point.
Graph of the system of equations:

As shown in the graph, the intersection point is indeed (-34/13, -25/13).