Review the details regarding an experiment.

Question

Jason intends to conduct an experiment demonstrating the conservation of mass by burning steel wool, which primarily consists of iron. During the combustion process, the iron in the steel wool reacts with oxygen to produce iron(III) oxide.

Which phase of his experiment holds the utmost significance for accurately showcasing the conservation of mass?

(1 point)

The steel wool should undergo combustion for an extended duration, preferably lasting a minimum of two hours.

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The steel wool should be ignited in an environment with ambient temperature, typically ranging from 20 to 25°C.

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The steel wool should be completely combusted to ensure that no iron remains in its initial form

The steel wool must undergo combustion within an airtight container or another enclosed system.

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Answer 1

The phase of Jason's experiment that holds the utmost significance for accurately showcasing the conservation of mass is:

The steel wool must undergo combustion within an airtight container or another enclosed system.

This is crucial because conducting the experiment in an enclosed system ensures that all the reactants (iron and oxygen) and products (iron(III) oxide and any other gases produced) are contained within the system. This allows for a measurable change in mass that illustrates the conservation of mass, as no mass is lost to the environment during the reaction.

Answer 2

What kind of reaction is depicted in the following equation?

2H202H2+O2

(1 point)

O decomposition

Osynthesis

Osingle replacement

Odouble replacement

Answer 3

The reaction depicted in the equation \( 2H_2O_2 \rightarrow 2H_2 + O_2 \) is a decomposition reaction.

In a decomposition reaction, a single compound breaks down into two or more simpler substances. In this case, hydrogen peroxide (\( H_2O_2 \)) breaks down to form hydrogen (\( H_2 \)) and oxygen (\( O_2 \)).

Answer 4

A double replacement chemical equation is shown.

MnO2 + HCI MnCl2 + H2O+_Cl₂

What values should be inserted into the blanks as coefficients to ensure the preservation of the law of conservation of matter?

(1 point)

Ο 1,4,1,2,1

1,2,1,2,1

2,3,1,2,1

2,4,2,4,1

Answer 5

To balance the chemical equation \( \text{MnO}_2 + \text{HCl} \rightarrow \text{MnCl}_2 + \text{H}_2\text{O} + \text{Cl}_2 \) while preserving the law of conservation of matter, we need to make sure that there are equal numbers of each type of atom on both sides of the equation.

1. Mn (Manganese): 1 on both sides.
2. O (Oxygen): 2 on the left (from \( \text{MnO}_2 \)) and 1 on the right (from \( \text{H}_2\text{O} \)).
3. H (Hydrogen): 1 on the left (from \( \text{HCl} \)) and 2 on the right (from \( \text{H}_2\text{O} \)).
4. Cl (Chlorine): 1 on the left (from \( \text{HCl} \)) and 2 on the right (1 from \( \text{MnCl}_2 \) and 1 from \( \text{Cl}_2 \)).

To balance this reaction, we can try the coefficients \( 2, 4, 2, 4, 1 \) in the following way:

\[ 2 \text{MnO}_2 + 4 \text{HCl} \rightarrow 2 \text{MnCl}_2 + 2 \text{H}_2\text{O} + \text{Cl}_2 \]

Now let's check the atom counts:

• Mn: \( 2 \) (left) vs \( 2 \) (right)
• O: \( 4 \) (left) vs \( 2 \) (right)
• H: \( 4 \) (left) vs \( 4 \) (right, \( 2 \) from \( H_2O \))
• Cl: \( 4 \) (left) vs \( 4 \) (right, \( 2 \) in \( MnCl_2 \) and \( 2 \) in \( Cl_2 \))

Thus, after balancing, the correct coefficients to represent the complete and balanced equation are:

2, 4, 2, 4, 1

So the answer is \( 2, 4, 2, 4, 1 \).