Replace all “/“ & “V”’s with Square root Then do the equation

Question

Jake runs 7/6 miles on Monday and 5V 6 miles on Tuesday. What is the difference in miles run each day? (1 point)
0 4V6
• 4V12
• 2/12
02/6

Answer 1

To solve the problem, we'll first replace all “/” & “V” ’s with the square root symbol.

Thus, the distances Jake runs can be rewritten as follows:

• Monday: 7/6 miles becomes 7√6 miles
• Tuesday: 5V6 miles becomes 5√6 miles

Now we can find the difference in miles run each day:

1. Distance on Monday: \( 7\sqrt{6} \)
2. Distance on Tuesday: \( 5\sqrt{6} \)

Now we calculate the difference: \[ \text{Difference} = 7\sqrt{6} - 5\sqrt{6} = (7 - 5)\sqrt{6} = 2\sqrt{6} \]

The correct answer from the given options is \( 2\sqrt{6} \), which corresponds to \( 02/6 \) based on the formatting of the options presented.

Final answer: 02/6

Answer 2

Replace all “/“ & “V”’s with Square root Then do the equation
Subtract 8V23 - V23. (1 point)
0 8/23
0 7/23
• 7V 46
• 8V46

Answer 3

To replace all “/” & “V” ’s with the square root symbol, the equation you provided will be transformed as follows:

• The expression \( 8V23 \) becomes \( 8\sqrt{23} \).
• The expression \( V23 \) becomes \( \sqrt{23} \).

Now, we can perform the subtraction:

\[ 8\sqrt{23} - \sqrt{23} \]

This can be simplified:

\[ (8 - 1)\sqrt{23} = 7\sqrt{23} \]

Now, looking at the options:

• \( 0 , 8/23 \)
• \( 0 , 7/23 \)
• \( 7\sqrt{46} \)
• \( 8\sqrt{46} \)

None of the options directly match \( 7\sqrt{23} \), but since it involves the square root and the closest format to our result, the expression could be rephrased, but there is no suitable answer among the options provided.

Please verify if there may have been a typographical error in the question or in the options. Based on the calculation performed, the correct answer is:

7√23.

Answer 4

Add 122 + 3V22 + V22. (1 point)
03/22 + 4V44
• 5V22
0 5/66
0 3/22 + 4/22

Answer 5

First, we need to replace all instances of “/” & “V” with the square root symbol in the expression you’ve provided.

The expression is: \[ 122 + 3V22 + V22 \]

Replacing “V” with the square root symbol:

• \( 3V22 \) becomes \( 3\sqrt{22} \)
• \( V22 \) becomes \( \sqrt{22} \)

Now the expression looks like this: \[ 122 + 3\sqrt{22} + \sqrt{22} \]

Next, combine like terms: \[ 122 + (3\sqrt{22} + \sqrt{22}) = 122 + 4\sqrt{22} \]

Now we can consider the options provided:

• \( 0 , 3/22 + 4\sqrt{44} \)
• \( 5\sqrt{22} \)
• \( 0 , 5/66 \)
• \( 0 , 3/22 + 4/22 \)

None of the options match the expression \( 122 + 4\sqrt{22} \) directly. Therefore, the correct simplified answer is:

122 + 4√22.

If the options should refer to specific numerical values or if you need further assistance in identifying correct answer options, please provide more context.

Answer 6

U have to pick 1 of the answers

Answer 7

Apologies for the confusion. Let’s review the expression we calculated and see if any of the provided options can represent it.

The expression we arrived at is: \[ 122 + 4\sqrt{22} \]

Now, let's evaluate the provided answer choices one more time:

1. \( 0 , 3/22 + 4\sqrt{44} \):

   • \( 4\sqrt{44} = 4 \cdot \sqrt{4 \cdot 11} = 8\sqrt{11} \) (this doesn't match)

2. \( 5\sqrt{22} \):

   • This is different as well.

3. \( 0 , 5/66 \):

   • This doesn't match \( 122 + 4\sqrt{22} \).

4. \( 0 , 3/22 + 4/22 \):

   • This simplifies to \( 0 + \frac{7}{22} \), which does not match either.

Given that none of the options directly match \( 122 + 4\sqrt{22} \), let’s consider the most relevant answer.

If I were to select the option that has a structure most similar to our result, it might be closest to \( 3/22 + 4/22 \) (though it doesn't fully represent the original terms).

However, without a perfect match, I would suggest choosing:

0 3/22 + 4/22

If these are indeed about maintaining the formatting and not direct numerical equivalence. Please let me know if further clarification or assistance is needed!