With a base length of 12 and a slant height of 18, we can find the surface area by plugging the values into the formula \(A = b^2 + 2bs\).
Substituting the values:
\[A = 12^2 + 2(12)(18)\]
\[A = 144 + 432\]
\[A = 576\]
Therefore, the surface area of the square pyramid is 576 square units.
rephrase this
Given that the base length is 12 and the slant height is 18, we can calculate the surface area using the formula \(A = b^2 + 2bs\).
So, substituting the values:
\[A = 12^2 + 2(12)(18)\]
\[A = 144 + 432\]
\[A = 576\]
The surface area of the square pyramid is 576 square units.
3 answers
make it look like a 7th grader wrote it
If the base is 12 and the slant is 18, we can find the area using the formula \(A = b^2 + 2bs\).
Plug in the numbers:
\[A = 12^2 + 2(12)(18)\]
\[A = 144 + 432\]
\[A = 576\]
The area of the square pyramid is 576 square units.
Plug in the numbers:
\[A = 12^2 + 2(12)(18)\]
\[A = 144 + 432\]
\[A = 576\]
The area of the square pyramid is 576 square units.