To find the vertices of triangle \( A'B'C' \) after reflecting triangle \( ABC \) across both the x-axis and the y-axis, we need to apply the reflection rules:
- Reflection across the x-axis: The point \( (x, y) \) becomes \( (x, -y) \).
- Reflection across the y-axis: The point \( (x, y) \) becomes \( (-x, y) \).
When reflecting a point across both axes, we can combine the transformations as follows:
For a point \( (x, y) \):
- Reflecting across the x-axis gives us \( (x, -y) \).
- Reflecting that result across the y-axis gives us \( (-x, -y) \).
Thus, to find the coordinates of \( A', B', \) and \( C' \), we can reflect \( A, B, \) and \( C \) using this combined transformation.
However, we need the original coordinates of \( A, B, \) and \( C \) to perform this. Since they are not provided in your question, I can't compute the result directly.
If you could provide the original coordinates of points \( A, B, \) and \( C \), I would be able to reflect them and determine the vertices of triangle \( A'B'C' \).