To find the time it will take to fill the pool using only the slower pipe, we can start by calculating the volume of the pool and understanding the rates of each pipe.
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Calculate the volume of the pool: The formula for the volume \(V\) of a rectangular prism (like a pool) is: \[ V = \text{length} \times \text{width} \times \text{average depth} \] Given:
- Length = 30 feet
- Width = 14 feet
- Average depth = 8 feet
Plugging in the numbers: \[ V = 30 , \text{ft} \times 14 , \text{ft} \times 8 , \text{ft} = 3360 , \text{ft}^3 \]
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Define the rates of the pipes: Let the rate of the slower pipe be \(r\) (in cubic feet per hour). According to the problem, the faster pipe fills at a rate that is \(1 + 2r\).
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Use the information about both pipes working together: When both pipes are working together, they fill the pool in 3.5 hours. Therefore, the combined rate of the two pipes can be formulated as follows: \[ \text{Combined rate} = r + (1 + 2r) = 3r + 1 , \text{ft}^3/\text{hr} \] Thus, the equation relating the combined rate and the volume of the pool is: \[ (3r + 1) \cdot 3.5 = 3360 \] This can be simplified to: \[ 3r + 1 = \frac{3360}{3.5} \] Evaluating the right side gives: \[ 3r + 1 = 960 \] Therefore, we can solve for \(r\): \[ 3r = 960 - 1 \implies 3r = 959 \implies r = \frac{959}{3} \approx 319.67 , \text{ft}^3/\text{hr} \] This gives us the rate of the slower pipe.
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Equation to fill the pool using only the slower pipe: Now if only the slower pipe is used, it will fill the pool at a rate of \(r\). The time \(t\) it will take to fill the pool can be formulated as: \[ r \cdot t = 3360 \] This can be rewritten to find \(t\): \[ t = \frac{3360}{r} \] Where \(r\) is the rate we obtained earlier.
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Final Rational Equation: Therefore, the final rational equation, using the slower pipe rate \(r\), can be written as: \[ t = \frac{3360}{r} \] This equation provides a way to find out how long it will take to fill the pool using only the slower pipe by substituting the value of \(r\) we calculated.