Reduce the fraction with a condition

y^2-16/3y+12

2 answers

this is the same as
(y-4)(y+4) / 3(y+4) = (y-4)/3 if y ≠ -4
OR

y² -16 y / 3 + 12 =

y² - 16 ∙ y / 3 + 108 / 9

( y² - 16 ∙ y / 3 + 64 / 9 ) + 44 / 9 =

[ y² - 2 ∙ y ∙ ( 8 / 3 ) + ( 8 / 3 )² ] + 44 / 9 =

( y - 8 / 3 )² + 44 / 9

y² -16 y / 3 + 12 = ( y - 8 / 3 )² + 44 / 9