Reduce the equation to standard form, classify the surface x^2-y^2+z^2-4x-2z=0

Question

I need step by step to the answer ((x-2)^2)/5 -(y^2)/5 +((z-1)^2)/5 =1

Answer 1

it's just the good old complete-the-square method from Algebra 2, right?
x^2-y^2+z^2-4x-2z=0
x^2-4x - y^2 + z^2-2z = 0
x^2-4x+4 - y^2 + z^2-2z+1 = 4+1
(x-2)^2 - y^2 + (z-1)^2 = 5
Think you can manage that last step?