factor out x in numerator and denominator to cancel,, it then becomes:
(x^2-4y^2)/(3x^2-2xy-8y^2)
factor both numerator and denominator:
[(x-2y)(x+2y)]/[(x-2y)(3x+4y)]
cancel (x-2y), therefore:
(x+2y)/(3x+4y)
so there,, :)
Reduce each rational expression
x^3-4xy^2/3x^3-2x^2y-8xy^2
1 answer