Red mercury (II) oxide decomposes to form mercury metal and oxygen gas according to the following equation: 2HgO (s) yields 2Hg (l) + O2 (g). If 4.00
moles of HgO decompose to form 1.50 moles of O2 and 603 g of Hg, what is the percent yield of this reaction?
2 answers
75%
posted just incase anyone else is looking for the answer^
3 answers