Question

Red and gray bricks were used to build a decorative wall. The number of red bricksnumber of gray bricks was 52 . There were 175 bricks used in all. How many red bricks were used?(1 point)
Responses

125
125

35
35

50
50

25

Answer 1

To solve this problem, let's assign variables to represent the number of red and gray bricks used.

Let R represent the number of red bricks used
Let G represent the number of gray bricks used

We are given two pieces of information in the problem:
1. The number of red bricks plus the number of gray bricks is 52: R + G = 52
2. The total number of bricks used is 175: R + G = 175

To solve this system of equations, we can use substitution or elimination. Let's use substitution.

From equation 1, we can express G in terms of R: G = 52 - R

Substituting this expression for G into equation 2, we get:
R + (52 - R) = 175
Simplifying the equation: 52 = 175

This equation does not make sense, so we made an error. Let's try using elimination.

From equation 1, we have R + G = 52.
From equation 2, we have R + G = 175.

Subtracting equation 1 from equation 2, we get:
(R + G) - (R + G) = 175 - 52
0 = 123

This equation is also incorrect. It seems that there is an error in the problem's given information, as the system of equations does not have a valid solution.