There are a total of 6 rectangular tables with 6 chairs each, which gives a total of 6 x 6 = <<6*6=36>>36 chairs at rectangular tables.
There are also a total of 5 round tables with 4 chairs each, which gives a total of 5 x 4 = <<5*4=20>>20 chairs at round tables.
Thus, there are a total of 36 + 20 = <<36+20=56>>56 chairs in the room.
Since the chairs are randomly numbered starting with 1, the probability that the first freshman to arrive will be seated at a round table is equal to the probability that the first chair they choose is at a round table.
The probability that the first chair they choose is at a round table is equal to the number of chairs at round tables, divided by the total number of chairs in the room.
Therefore, the probability is 20/56 = <<20/56=0.357>>0.357.
So the probability that the first freshman to arrive will be seated at a round table is 0.357 or 35.7%. Answer: \boxed{0.357}.
rectangular tables with 6 chairs each and 5 round tables with 4 chairs each. The chairs are randomly numbered starting with 1 and the freshman will be randomly assigned a seat number.
What is the probability that the first freshman to arrive will be seated at a round table?
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